--- In mepbmlist@y..., blchezluis@a... wrote:
> > It's random for the first day of movement. After that it is
> > dependent on the MPs.
> >
> > Clint
>
> So, the randomness is helpful when both armies have the same
amount
of
> MP to use to get into their hexes, but when there is a difference
in
> the MP, the one who has the least MP to get into his target hex,
gets
> there first and stops the others movement?
This is what I had been told before, and always assumed. It is as
expained in the other reply below. I will try and simplify or give
another way of speaking, without all the algebra!
The 25 nations move one at a time, randomly chosen who moves first.
Once the First Day (the game goes every 2 weeks, eh?) is over, then
it's all based on movement points (days "crossing" hexes, etc.).
When you move on day one, it is assumed that you move into the other
hex immediately. Even if it's mountains, you move into that hex
right away. You will be sitting there for 11 more days, but you are
there the first day.
If there is someone in the mountains moving to the plains, he who
moves first (which nation moves first) moves, and the other is stuck
against "non-friendly/tolerant" forces. Coin toss.
I personally had a real hard time dealing with that when I had to
move my HI into a Hills and Rough hex to trap Cav moving onto the
plains. Doesn't make sense does it? But, for simplicity, the game
operates that way.
This way, you move onto the mountains immediately, and then spend
another 11 days there before you can leave. The only other way to
do it, is to be sitting on the plains hex for 11 days, and then on
the 12 move to the mountain hex. But even there, you will have the
issue of did you leave on the 12th day, before that other army
entered your plains hex on the 12th day....it's always a "who goes
first" issue. The question is WHEN does WHO go first. The answer
is DAY 1.
Hope this helps, and if anyone else can put it differently, I'm sure
there are enough of us out there who need to understand it more
clearly!
Regards,
brad brunet
Sort of, you are trying to read into it too much.
An army in hex "a" is moving in a straight line through
hexes "b,c,d,e,f,g" and trying to end up in hex "h". In our
example
hexes are in the plains for hexes "b-e" and in the rough for "f-h".
The army moving is calvary and has food. Two similiar armies are
located in hexes "b" and "h". Starting army "b" is trying to move
one hex SW without getting caught and army "h" is trying to move in
a
straight line to hex "a" opposite army "a". For cav the movement
for
army "a" is as such: 1&2) plains hex"b" 3&4) plains hex"c" 4&5)
plains hex "d" 6,&7) plains hex "e" 9,10,&11) hills and rough
hex "f" 12,13,&14) hills and rough hex "g" and there stopping due
to
insuffiecient movement.
In this example there are two movement phases in which this army
can
be stopped by non-friendly, non-tolerant armies. The first one is
movement phase one, which is the only movement phase in which
movement is randomised. As army "a" moves E there is roughly a 50-
50
chance that it will move before army "b" stopping in hex "b". The
random factor comes in, due to the fact that armies move in a hex
at
the begining of an impulse. In other words if it take you four
MP's
to move into a hex you move into that hex on 1 and stay in there 3
more pulses not wait three in the previous hex and move in on the
fourth. So if army "a" moves first all movement is halted in hex
"b"
by army "b" and therefore army "c" will also stop in that hex on
impulse 13. If army "b" has its movement first it will then
proceed
to SW and get itself clear of the equation, ending the
randominization of this example. Now army "a" will continue its
Eastward movement spending all its Movement phases as noted
previoulsy. Army "c" will however be moving in the opposite
direction and since there is no more random factor these armies
will
stop each other's movement at hex "e" both during their 7th
movement
phase. Sometimes the blocking hex is somewhat determined by who
moved first, during the entire phase, an example would be an
outside
army one hex NE of hex"c" moving into hex "c" on movement phase 5
has
a 50-50 chance of catching army "a" in hex"C" before army "a" could
move into hex"d" during its movement phase. This however was
predetermined in the first movement phase by who moved first.
Although this seems confusing, do not worry it is confusing.
Though
···
I hope it does help you somewhat.
Sincerely,
Bluecheese <wwhhhd>
